b^2-2b+20=0

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Solution for b^2-2b+20=0 equation:


Simplifying
b2 + -2b + 20 = 0

Reorder the terms:
20 + -2b + b2 = 0

Solving
20 + -2b + b2 = 0

Solving for variable 'b'.

Begin completing the square.

Move the constant term to the right:

Add '-20' to each side of the equation.
20 + -2b + -20 + b2 = 0 + -20

Reorder the terms:
20 + -20 + -2b + b2 = 0 + -20

Combine like terms: 20 + -20 = 0
0 + -2b + b2 = 0 + -20
-2b + b2 = 0 + -20

Combine like terms: 0 + -20 = -20
-2b + b2 = -20

The b term is -2b.  Take half its coefficient (-1).
Square it (1) and add it to both sides.

Add '1' to each side of the equation.
-2b + 1 + b2 = -20 + 1

Reorder the terms:
1 + -2b + b2 = -20 + 1

Combine like terms: -20 + 1 = -19
1 + -2b + b2 = -19

Factor a perfect square on the left side:
(b + -1)(b + -1) = -19

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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